老牌歌星辛迪·勞帕客串出演《識(shí)骨尋蹤》第五季第一集

《識(shí)骨尋蹤》第五季第一集叫做“噴泉里的先知”,將于9月17日回歸,這集中請(qǐng)來(lái)了老牌歌星辛迪·勞帕客串出演。

《識(shí)骨尋蹤》第五季發(fā)布首款預(yù)告超Q劇情

Cyndi Lauper guest-stars as Avalon Harmonia, a psychic who provides leads to Brennan and Booth and subsequently becomes a suspect in their murder investigation, in the BONES season premiere episode “Harbingers in the Fountain” airing Thursday, Sept. 17 (8:00-9:00 PM ET/PT)

辛迪·勞帕扮演的是一位靈媒

客串的辛迪·勞帕扮演的是一位叫做Avalon Harmonia的靈媒。注意她的角色名兒哦。Avalon是凱爾特神話中的仙境,傳說(shuō)中亞瑟王的安葬地;而Harmonia則是希臘神話中掌管聲樂(lè)和諧的女神。實(shí)在是非常神婆的一個(gè)名字啊。

《識(shí)骨尋蹤》第五季要和《別對(duì)我撒謊》玩穿越?

Brennan (Emily Deschanel, L) listens as psychic Avalon Harmonia (guest star Cyndi Lauper, R) gives her information about a case

辛迪·勞帕扮演的神婆向Brennan分析案情

其實(shí)《識(shí)骨尋蹤》與辛迪·勞帕頗有淵源,早在第三季就有角色翻唱了她的歌頗受好評(píng)。而制片人表示這次卻也不會(huì)上演班門(mén)弄斧的劇情。

美劇養(yǎng)眼3位帥哥男主角華麗麗的MV客串

Booth (David Boreanaz, R) confronts Avalon Harmonia (guest star Cyndi Lauper, L), a psychic who helped provide leads in a case

辛迪·勞帕扮演的女巫反成嫌疑犯

辛迪·勞帕扮演的靈媒先前還在幫助破案二人組找到線索,轉(zhuǎn)而卻又成為了嫌犯被審問(wèn)。

父親節(jié)影視:美劇中最酷的非主流老爸

Booth (David Boreanaz, R) questions Avalon Harmonia (guest star Cyndi Lauper, L), a psychic who helped provide leads in a murder investigation but then became a prime suspect

Booth和Brennan在案發(fā)現(xiàn)場(chǎng)尋找證物

經(jīng)過(guò)上一季的波折,看到Brennan和Booth重又回到罪案現(xiàn)場(chǎng)并肩破案真是覺(jué)得有愛(ài)?。?/font>

《識(shí)骨尋蹤》第四季大結(jié)局感人旁白中英對(duì)照

Brennan (Emily Deschanel, L) and Booth (David Boreanaz, R) search for evidence after a psychic provides them with valuable information

Booth和Brennan金牌搭檔回歸

Booth帶著墨鏡扶著這個(gè)儀器的樣子還真有點(diǎn)像盲人……

《識(shí)骨尋蹤》續(xù)訂兩季 《終結(jié)者外傳》不幸終結(jié)

Brennan (Emily Deschanel, L) and Booth (David Boreanaz, R) search for evidence after a psychic provides them with valuable information

神婆與Brennan和Angela坐在一起測(cè)算塔羅

辛迪·勞帕扮演的靈媒原來(lái)是Angela的好友,她攤出了一桌子塔羅牌不知要測(cè)算些什么呢?

另類(lèi)美劇口語(yǔ):“很拽”用英文要怎么說(shuō)?

Brennan (Emily Deschanel, R) and Angela (Michaela Conlin, C) listen to Angela’s psychic, Avalon Harmonia (guest star Cyndi Lauper, L)